-3=-0.5x^2+x+4

Solution for -3=-0.5x^2+x+4 equation:

-3=-0.5x^2+x+4

We move all terms to the left:

-3-(-0.5x^2+x+4)=0

We get rid of parentheses

0.5x^2-x-4-3=0

We add all the numbers together, and all the variables

0.5x^2-1x-7=0

a = 0.5; b = -1; c = -7;
Δ = b2-4ac
Δ = -12-4·0.5·(-7)
Δ = 15
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{15}}{2*0.5}=\frac{1-\sqrt{15}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{15}}{2*0.5}=\frac{1+\sqrt{15}}{1}
$